# SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

Algebra ->  Algebra  -> Triangles -> SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.      Log On

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 Geometry: Triangles Solvers Lessons Answers archive Quiz In Depth

 Question 81959: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website! Let x=length of base then 4x-8=length of one of the equal legs Now we are told that: x+2(4x-8)=29 get rid of parens x+8x-16=29 add 16 to both sides x+8x-16+16=29+16 collect like terms 9x=45 divide both sides by 9 x=5 cm---------------------length of base 4x-8=4(5)-8=12cm------------length of one of the equal legs CK 12+12+5=29 29=29 Hope this helps---ptaylor