SOLUTION: I have a figure of a triangle the measurements on all three sides are 3/4x,5/x^2,1/x^2. I have find an expression that represents its perimeter. I have my answer down as 9/4x^4 am

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Question 81678: I have a figure of a triangle the measurements on all three sides are 3/4x,5/x^2,1/x^2. I have find an expression that represents its perimeter. I have my answer down as 9/4x^4 am I right?
Answer by rapaljer(4551) About Me  (Show Source):
You can put this solution on YOUR website!
If the sides are 3/4x,5/x^2,1/x^2, then you must ADD these sides together to get the perimeter. This means you need to find a common denominator, which is 4x^2. It looks like this:
+%283%2F%284x%29%29+%2B%285%2F%28x%5E2%29%29+%2B+1%2F%28x%5E2%29+, where the LCD= 4x%5E2
+%283%2F%284x%29%29%2A%28x%2Fx%29+%2B%285%2F%28x%5E2%29%29%2A%284%2F4%29+%2B+%281%2F%28x%5E2%29%29%2A%284%2F4%29+
+%28%283x%29%2F%284x%5E2%29%29+%2B+20%2F%284x%5E2%29+%2B+4%2F%284x%5E2%29+
+%283x%2B24%29%2F%284x%5E2%29

R^2 at SCC