SOLUTION: Let Medium = x
Therefore longest = x+10
And the shortest = x-5
So x+x+10+x-5=65
3x+5=65
3x=60
x=20
Therefore the sizes of the three sides of the triangle from the longest ar
Algebra ->
Triangles
-> SOLUTION: Let Medium = x
Therefore longest = x+10
And the shortest = x-5
So x+x+10+x-5=65
3x+5=65
3x=60
x=20
Therefore the sizes of the three sides of the triangle from the longest ar
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Question 813398: Let Medium = x
Therefore longest = x+10
And the shortest = x-5
So x+x+10+x-5=65
3x+5=65
3x=60
x=20
Therefore the sizes of the three sides of the triangle from the longest are 30, 20 and 15 respectively Answer by Tunechi(1) (Show Source):
You can put this solution on YOUR website! Let Medium = x
Therefore longest = x+10
And the shortest = x-5
So x+x+10+x-5=65
3x+5=65
3x=60
x=20
Therefore the sizes of the three sides of the triangle from the longest are 30, 20 and 15 respectively
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