SOLUTION: Let Medium = x Therefore longest = x+10 And the shortest = x-5 So x+x+10+x-5=65 3x+5=65 3x=60 x=20 Therefore the sizes of the three sides of the triangle from the longest ar

Question 813398: Let Medium = x
Therefore longest = x+10
And the shortest = x-5
So x+x+10+x-5=65
3x+5=65
3x=60
x=20
Therefore the sizes of the three sides of the triangle from the longest are 30, 20 and 15 respectively
Answer by Tunechi(1) (Show Source): You can put this solution on YOUR website!
Let Medium = x
Therefore longest = x+10
And the shortest = x-5
So x+x+10+x-5=65
3x+5=65
3x=60
x=20
Therefore the sizes of the three sides of the triangle from the longest are 30, 20 and 15 respectively
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