SOLUTION: Is ΔABC with vertices A(–2, 3), B(2, 0), and C(–1, –4) a right triangle?
Please answer with:
ΔABC is a right triangle because or
ΔABC is not a right tria
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Question 810650: Is ΔABC with vertices A(–2, 3), B(2, 0), and C(–1, –4) a right triangle?
Please answer with:
ΔABC is a right triangle because or
ΔABC is not a right triangle.
Thank You.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
A(–2, 3), B(2, 0), and C(–1, –4)
find the distance between AB, BC, & CA
AB
Distance between two points
x1 y1 x2 y2
-2 3 2 0
d=
d=
d=
d=
d= 5.00
distance BC
Distance between two points
x1 y1 x2 y2
2 0 -1 -4
d=
d=
d=
d=
d= 5.00
Distance CA
x1 y1 x2 y2
-2 3 -1 -4
d=
d=
d=
d=
d= 7.07
AB=5,BC=5 & AC=7.07
ab^2+BC^2= is not equal to AC^2
therefore it is not a right triangle
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