SOLUTION: if the hypotenuse of a right triangle is 52 in. one leg of the triangle is 8 in more than twice the length of the other. what is the perimeter of the triangle?

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Question 806389: if the hypotenuse of a right triangle is 52 in. one leg of the triangle is 8 in more than twice the length of the other. what is the perimeter of the triangle?
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
c=52, a=2b+8
a^2+b^2=c^2
(2b+8)^2+b^2=52^2
4b^2+32b+64+b^2=2704
5b^2+32b-2640=0 see below
b=20, a=48
48+20+52
=120"
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Ed
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=53824 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 20, -26.4. Here's your graph:
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