SOLUTION: find the area of the triangle whose longest and shortest sides are 62 cm and 31 cm respectively and whose biggest angle is 140

Question 776252: find the area of the triangle whose longest and shortest sides are 62 cm and 31 cm respectively and whose biggest angle is 140
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Two shorter sides are 31 and d in length and longest side is 62, opposite of the given angle. The given angle is between the 31 and d lengths.

Law of Cosines:

---------- a quadratic equation in d.

Finding value for d just requires computation through the general solution to the quadratic formula. After than, you can get the height of the triangle according to . Area of the triangle would be . That just uses area as .
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