SOLUTION: an isosceles triangle has an area of 48 ft squared. If the base is 12 ft what is the length of each leg?

Question 756870: an isosceles triangle has an area of 48 ft squared. If the base is 12 ft what is the length of each leg?
Answer by sachi(548) (Show Source): You can put this solution on YOUR website!
area of the isoceles triangle=1/2 base*altitude
base=12 & area=48
so altitude=48*2/12=8
now the altitude divides the triangle into two right angled triangles
so each leg of the trianle=sq root [(altitude)^2+(1/2base)^2]
=sq root [(8)^2+(1/2*12)^2]=sq root [64+36]=sq root 100=10

RELATED QUESTIONS
An isosceles triangle has area of 130 ft2. If the base is 10 ft, what is the length of... (answered by TimothyLamb)

The length of one leg of an isosceles right triangle is 3 ft. What is the perimeter of... (answered by ewatrrr)

If an isosceles triangle has a perimeter of 345 cm and base length of 85 cm, what is the... (answered by richwmiller)

An isosceles right triangle has a hypotenuse of 12. What is the measure of each... (answered by ikleyn)

An isosceles right triangle has area of 98cm squared. Find the length of eacg... (answered by stanbon)

the length of each leg of an isosceles triangle is 5 centemeters more than twice the... (answered by stanbon)

The length of each leg of an isosceles triangle is 7 inches less than twice the length of (answered by mananth)

Each of the legs of an isosceles triangle is 6 ft shorter than the base. The perimeter... (answered by srinivas.g)