SOLUTION: Multi-Step Problem. You can use the method described below to approximate the distance across a stream without getting wet. As shown in the diagram you need a - Stand on the edge
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Question 68325This question is from textbook Geometry
: Multi-Step Problem. You can use the method described below to approximate the distance across a stream without getting wet. As shown in the diagram you need a - Stand on the edge of the stream and look straight across to a point on the other edge of the stream. Adjust the visor of your cap so that its in the line with that point.
- Without changing the inclination of your neck and head, turn sideways until the visor is in line with a point on your side of the stream.
- Measure the distance BD between your feet and that point.
QUESTIONS
a.) From the description of the measuring method, what corresponding parts of the 2 triangles can you assume are congruent?
b.) What theorem or postulate can be used to show that the 2 triangles are congruent?
c.) Explain why the length of BD is also the distance across the stream.
This question is from textbook Geometry
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Without changing the inclination of your neck and head, turn sideways until the visor is in line with a point on your side of the stream.
- Measure the distance BD between your feet and that point.
QUESTIONS
a.) From the description of the measuring method, what corresponding parts of the 2 triangles can you assume are congruent?
The angle your body makes with the ground is a rt. angle; The angle made
by your body and the line to the opposite shore and/or the distant object
The side from your feet to the opposite shore and/or the side from your
feet to the distant object. The side formed by your body in both triangles.
b.) What theorem or postulate can be used to show that the 2 triangles are congruent? Side-Angle-Side
c.) Explain why the length of BD is also the distance across the stream.
Corresponding parts of congruent triangles.
Cheers,
Stan H.
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