SOLUTION: ABC is a triangle with sides a, b, and c, as shown in the diagram. If angle C = 90 degrees, c = 4, and a + b = the square root of 18, then the area of the triangle is... A)1/2 B)1

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Question 665289: ABC is a triangle with sides a, b, and c, as shown in the diagram. If angle C = 90 degrees, c = 4, and a + b = the square root of 18, then the area of the triangle is... A)1/2 B)1 C)2 D)4 E)18
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
ABC is a triangle with sides a, b, and c, as shown in the diagram. If angle C = 90 degrees, c = 4, and a + b = the square root of 18, then the area of the triangle is... A)1/2 B)1 C)2 D)4 E)18
Since a + b = Ö18, b = Ö18 - a. 



The area is A = ab = a(Ö18 - a)

By the Pythagorean theorem:

a² + b² = c²

a² + (Ö18 - a)² = 4²

a² + 18 - 2aÖ18 + a² = 16

2a² - 2aÖ18 = -2

Divide through by 2

a² - aÖ18 = -1

Multiply through by -1

-a² + aÖ18 = +1

aÖ18 - a² = 1

Factor out a on the left:

a(a - Ö18) = 1

Notice that the area above is A = a(Ö18 - a), which just
happens to be the left side multiplied by . So let's
multiplty both sides of that equation through by :

a(a - Ö18) = ·1

So Area = a(a - Ö18) = 

Answer:  

Edwin

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