Hi,

The length of the base of an isosceles triangle is x. 

The length of a leg is 2x-5. (other leg the same length)

Question states*** perimeter of the triangle is 20

 x + (2x-5) + (2x-5) = 20

     5x - 10 = 20

       5x = 30

        x = 6, the length of th ebase.  The length of each leg is 7 

RELATED QUESTIONS

The length of the base of an isosceles triangle is 4x -7. The length of a leg is x. The... (answered by Edwin McCravy)

The length of the base is an isoceles triangle is x. The length of a leg is 2x-5 the... (answered by josgarithmetic)

The base of an isosceles triangle is 3 cm longer than a leg. The perimeter of the... (answered by ewatrrr)

the length of each leg of an isosceles triangle is 5 centemeters more than twice the... (answered by stanbon)

how to find the length of a leg of an isosceles triangle is twice the length of the base.  (answered by ewatrrr)

The leg of an isosceles triangle is 6 more than twice the base, if the perimeter is 42cm... (answered by Cromlix)

the base of an isosceles triangle and one of its legs have lengths that are consecutive... (answered by checkley71)

The length of each leg of an isosceles triangle is 7 inches less than twice the length of  (answered by mananth)

The perimeter of an isosceles triangle is 70dm. If the length of a leg of the triangle is  (answered by edjones)