One angle of a triangle is twice another. The third angle is three times the smallest. Find the measure of the smallest angle. Let the smallest angle be A Let the middle-sized angle be B Let the largest angle be C. There are two possibilities because the first sentence is ambiguous. 1. If the middle-sized angle is twice the smallest angle, then, B = 2A C = 3A A + B + C = 180 Do you know how to solve that system of equations? If not post again asking how. Solve that system and get A = 30°, B = 60°, C = 90° so the smallest angle is A or 30°. ------------------------------------------ 2. If the largest angle is twice the middle-sized angle, then C = 2B C = 3A A + B + C = 180 Solve that system and get: A = 32 8/11°, B = 49 1/11°, 98 2/11° so the smallest angle is 32 8/11° Edwin