SOLUTION: find perimeter of triangle whose vertices are (4,10), (9,-4),(8,1)

Question 639795: find perimeter of triangle whose vertices are (4,10), (9,-4),(8,1)
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
P(4,10), Q(9,-4),R(8,1)
Find the distance PQ, QR, RS
P(4,10), Q(9,-4)
x1 y1 x2 y2

4 10 9 -4
d=
d=
d=
d=
d(P,Q)= 14.87
Q(9,-4),R(8,1)
x1 y1 x2 y2

9 -4 8 1
d=
d=
d=
d=
dQ,R)= 5.10
RR(8,1),P(4,10)
x1 y1 x2 y2

8 1 4 10
d=
d=
d=
d=
d= 9.85
Add up all the three distances

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