SOLUTION: How do you find the side lengths of a triangle when you have the perimeter OR the area, and the ratios of the sides. Example of a problem. Triangle ABC. AB has a scale of 2. BC has

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Question 590102: How do you find the side lengths of a triangle when you have the perimeter OR the area, and the ratios of the sides. Example of a problem. Triangle ABC. AB has a scale of 2. BC has a scale of 4 and CA has a scale of 5. The area of the triangle is 450 cm2.
Thanks.

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
AB has a scale of 2. BC has a scale of 4 and CA has a scale of 5.
Let k be the constant that you have to multiply 2 by to get the length of AB,
4 by to get the lebnth of BC, and 5 by to get the kength of CA 

AB = 2k, BC = 4k, CA = 5k

Now we use Heron's formula for the area:

Area = 

a = AB = 2k, b = BC = 4k, c = CA = 5k

s = semiperimeter =  =  =  = 

s-a = -2k = - =

s-b = -4k = - =

s-c = -5k = - =

Substituting in

Area = 

450 = 

450 = 

Square both sides:

202500 = 

Multiply both sides by 16

3240000 = 231k4

Divide both sides by 231

 = k4

Take fourth roots of both sides:

 = k

10.88261481 = k

AB = 2k = 2(10.88261481) = 21.76522962 
BC = 4k = 4(10.88261481) = 43.53045924 
CA = 5k = 5(10.88261481) = 54.41307405

[It's much easier if you are given the perimeter instead of the area]

Edwin

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