SOLUTION: if you have a isosceles triangle with the legs being 9 and the base is 10 find the altitude. how do you solve it. we learn a equation leg squared = half part and base but if you so

Question 570878: if you have a isosceles triangle with the legs being 9 and the base is 10 find the altitude. how do you solve it. we learn a equation leg squared = half part and base but if you solve it you wouldn't get the base to be 10.
Found 2 solutions by mananth, stanbon:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
height of isoscles triangle = sqrt(a^2-(b/2)^2)

where a is the length of the leg
and b the base

h=8.64

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if you have an isosceles triangle with the legs being 9 and the base is 10 find the altitude.
-------------
Draw the picture:
Draw a perpendicular bisector to the base: (that is the height)
---
You have two right triangles with base = 5 ; height = "h" ;
and hypotenuse = 9
----
Pythagoras:
9^2 = 5^2 + h^2
h^2 = 81-25 = 56
h = sqrt(56) (that is the altitude of the isosceles triangle)
=================
Cheers,
Stan H.
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