# SOLUTION: Please help me solve these problem. Ignoring air resistance, the distance d in feet that an object falls in t seconds is given by the formula d=1/2gt^2, where g is approximately 3

Algebra ->  Algebra  -> Triangles -> SOLUTION: Please help me solve these problem. Ignoring air resistance, the distance d in feet that an object falls in t seconds is given by the formula d=1/2gt^2, where g is approximately 3      Log On

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 Question 563775: Please help me solve these problem. Ignoring air resistance, the distance d in feet that an object falls in t seconds is given by the formula d=1/2gt^2, where g is approximately 32 ft.per second sq. this formula can also be express as d=16t^2. a. A plant falls from a window ledge 144 feet high. How long does it takes to hit the street below? b. A piece of concrete falls from a bridge 400 feet high,how long does it takes to hit the water below? Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!Ignoring air resistance, the distance d in feet that an object falls in t seconds is given by the formula d = (1/2)gt^2, where g is approximately 32 ft.per second sq. this formula can also be express as d=16t^2. a. A plant falls from a window ledge 144 feet high. How long does it takes to hit the street below? Solve: 144 = 16*t^2 t = sqrt(144/16) = 12/4 = 3 seconds ------------------------------------------ b. A piece of concrete falls from a bridge 400 feet high,how long does it takes to hit the water below? Solve: 400 = 16t^2 t^2 = (400/16) = 20/4) = 5 seconds ==================================== Cheers, Stan H. ===================