The largest angle is at Q. It looks like a right angle. If it is, then the slopes of the lines PQ and QR will be opposite signed reciprocals Find the slope of PQ m = m = m = m = -5 Find the slope of QR m = m = m = m = -5 and are opposite signed reciprocals, that is, their product is -5· = -1. So PQ and QR are perpendicular, so angle Q is 90° Edwin