# SOLUTION: What is the measure of the third sides of a triangle, that is already measured with 5meters and 4meters?

Algebra ->  Algebra  -> Triangles -> SOLUTION: What is the measure of the third sides of a triangle, that is already measured with 5meters and 4meters?      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Geometry: Triangles Solvers Lessons Answers archive Quiz In Depth

 Question 530640: What is the measure of the third sides of a triangle, that is already measured with 5meters and 4meters?Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!There is no answer to this question because the triangle could any shape. If the angle between the two known sides was 1 degree, then the third side would relatively short. If the angle between the two known sides was 179 degrees, then the third side would be relatively long. . If you have studied the law of cosines, you know that it extends the Pythagorean Theorem to any angle. c^2 = a^2 + b^2 - 2*a*b*cos(x), where x is the angle between the known sides a and b. . (I used 'x' where most texts would say the angle was a Greek letter. But I don't have a Greek letter to type into this reply. Sorry.) . To use the law of cosines, you have to know the measure of the angle. . cos 1° = 0.99984769515639 . c^2 = 4^2 + 5^2 - 2*(4)*(5)*(0.99984769515639) . c^2 = 1.00609219 . c = sqrt(1.00609219) = 1.00304147 . VS. . cos 179° = -0.99984769515639 . c^2 = 4^2 + 5^2 - 2*(4)*(5)*(-0.99984769515639) . c^2 = 80.9939078 . c = sqrt(80.9939078) = 8.99966154 . Done.