SOLUTION: What is the area of an isosceles triangle with the base angles of 57degrees and a base of 15
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Question 522770: What is the area of an isosceles triangle with the base angles of 57degrees and a base of 15
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the area of an isosceles triangle with the base angles of 57degrees and a base of 15
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Sketch the triangle with base 15 and base angles 57 degrees.
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Draw a perpendicular bisector of the base.
That bisector is the altitute of the triangle.
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You have a right triangle on the right side
with base = 15/2 = 7.5
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Solve tan(57) = alt/7.5
altitude = 7.5*tan(57) = 11.55
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Area = (1/2)base*altitude
A = (1/2)*7.5*11.55 = 43.31 sq units
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Cheers,
Stan H.
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