SOLUTION: In a triangle ABC, angle B is 4 times angle A and angle C is 16 degrees less than 5 times angle A. I can find angle A, but am lost on how to find B and C.

Question 518662: In a triangle ABC, angle B is 4 times angle A and angle C is 16 degrees less than 5 times angle A.
I can find angle A, but am lost on how to find B and C.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a triangle ABC, angle B is 4 times angle A and angle C is 16 degrees less than 5 times angle A.
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Equations:
A + B + C = 180 degrees
B = 4A
C = 5A - 16
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Substitute for "B" and for "C" and solve for "A":
A + 4A + 5A-16 = 180
10A = 196
A = 19.6 degrees
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B = 4A = 78.4 degrees
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C = 5A-16 = 5*19.6-16 = 82 degrees
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Cheers,
Stan H.
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