SOLUTION: The lengths of the bases of an isosceles trapezoid are 6 centimeters and 12 centimeters. If the length of each leg is 5 centimeters, what is the area of the trapezoid?

Question 481978: The lengths of the bases of an isosceles trapezoid are 6 centimeters and 12 centimeters. If the length of each leg is
5 centimeters, what is the area of the trapezoid?
Found 2 solutions by cleomenius, MathTherapy:
Answer by cleomenius(959) (Show Source): You can put this solution on YOUR website!
Area = 1/2 (b1 + b2)h
Area = 1/2( 6 + 12) * 5
Area = 45 cm^2
Cleomenius.
Answer by MathTherapy(10551) (Show Source): You can put this solution on YOUR website!

Since one of the legs of the trapezoid is 5 cm, then the h (height) = 4, since a 3-4-5 right triangle would be formed by a segment of the longer base, the height, and one of the legs.

Formula for the area of an isosceles trapezoid = , with bases being and and height "h"

Since h (h) height = 4 cm, and bases, and being 6 and 12 cm, we get:

Area = ------ = =
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