SOLUTION: Isoscles triangle ABC has vertices A(-1,1), B(1,5), and C(3,1) What is the equation of the perpendicular bisector of line segment BC?

Question 455572: Isoscles triangle ABC has vertices A(-1,1), B(1,5), and C(3,1) What is the equation of the perpendicular bisector of line segment BC?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Isoscles triangle ABC has vertices A(-1,1), B(1,5), and C(3,1) What is the equation of the perpendicular bisector of line segment BC?
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The midpoint of BC is x = (1+3)/2 ; y = (5+1)/2 or (2,3)
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BC has slope (5-1)/(1-3) = -2
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So the perpendicular bisector is the line
with slope 1/2 passing thru point (2,3)
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Form y = mx + b
Substitute for y,x, and m, and solve for "b":
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3 = (1/2)2 + b
3 = 1 + b
b = 2
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Equation:
y = (1/2)x + 2
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Cheers,
Stan H.
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