SOLUTION: how does sin B = 0.6608 get transfromed into B = 41Degrees what step am i missing from changing 0.6608 to an angle (arrgggg)
using law of sines
when 33/SIN 57 degree = 26/ SIN B
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Question 410488: how does sin B = 0.6608 get transfromed into B = 41Degrees what step am i missing from changing 0.6608 to an angle (arrgggg)
using law of sines
when 33/SIN 57 degree = 26/ SIN B
next step is
33sinB = 26sin57degree
next step
sin B = 26sin57degree/33 =0.6608
sin B = 0.6608
what do i do to get this
then B = 41 degree (it all checks on a caulator) how do I get that SIN B = 0.6608 to = 41 degrees into an angle of a triangle
how do you change that to this B = 41degree
what am i missing (aaarrrrrggh)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
sine (B) = .6608
to find the angle whose sine is .6608, you find the arcsin, or sin(-1) of .6608
use your calculator and enter .6608.
use the arcsin function of your calculator to get 41.36091391
this rounds down to 41 degrees.
on my calculator the arcsin function is the 2d key followed by the sin key.
example:
enter .6608
his the 2d key
hit the sin key
answer is 41.36091391
your calculator might do it differently, but the result should be the same.
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