We draw the triangle:We extend BC, and draw a line segment from A perpendicular to the extension of BC, intersecting it at D: Angle ACD is 60° because it is supplementary to angle ACB which is 120°, and 180°- 120° = 60° Triangle ADC is a "30°60°90°" right triangle, and since its _ hypotenuse AC is 2, its lower leg CD is 1, and its vertical leg AD is √3. BD = BC + CD = 6 + 1 = 7 Triangle ADB is a right triangle, therefore tan(B) = = Use inverse tangent function to get Angle B = 13.89788625° closest to 14°. Edwin