SOLUTION: I have side a= x-2, side b=x and side c=x+2 and it is a right triangle.. I am supposed to solve for x
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Question 398475: I have side a= x-2, side b=x and side c=x+2 and it is a right triangle.. I am supposed to solve for x
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
(x-2)^2+x^2=(x+2)^2
x^2-4x+4+x^2=x^2+4x+4
x^2-8x=0
x(x-8)=0
x=0 or x=8
Answer: x=8
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