SOLUTION: How do you solve a problem that says "find the value of each ratio to the nearest hundredth." and then gives you a problem saying "sin14"

Algebra.Com
Question 393481: How do you solve a problem that says "find the value of each ratio to the nearest hundredth." and then gives you a problem saying "sin14"
Answer by neatmath(302)   (Show Source): You can put this solution on YOUR website!

Well, remember what the sine of an angle of a triangle is?

It simply is the length of the side opposite the angle, divided by the length of the hypotenuse.

In other words, it is a ratio!

The value for the sin(14) where 14 is in degrees is:

.24192189

Therefore the opposite side divided by the hypotenuse has a value of .24192189

So you indeed have a ratio:



where o is the length of the opposite side, and h is the length of the hypotenuse.

You can see that if you had a side opposite of 24, and a hypotenuse of 100,

then you would have the ratio of

which would also be the sine of that angle (and of course that angle would be approximately 14 degrees).

Without seeing your actual books or lessons, I am assuming that this is what they are looking for.

I hope this helps!

RELATED QUESTIONS

how do you solve a problem that says parallel to the y-axis and passes through (-5,-2)?... (answered by funmath)
How do you find the volume of a solid round to the nearest... (answered by Alan3354)
Please show me how to solve the problem and then round it out to the nearest hundredth.... (answered by Alan3354,palanisamy)
Good day! I am so confused regarding the following question: Solve the problem. Round... (answered by jim_thompson5910)
could you help me solve the following ellipse problem? The problem gives me that the... (answered by fastblue,stanbon)
This is a problem that I need to solve by system of elimination and then check the... (answered by jgr45)
How do you find a percent change? Then round to the nearest tenth of a percent? Problem... (answered by stanbon)
when a teacher gives you a problem that says determine wther the given lengths are sides... (answered by ankor@dixie-net.com)