SOLUTION: A point P(x,y) is such that its distance form the y-axis is equal to its distance from the point A(3,2).show that y^2 - 4y - 6x + 13 = 0

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Question 367677: A point P(x,y) is such that its distance form the y-axis is equal to its distance
from the point A(3,2).show that y^2 - 4y - 6x + 13 = 0

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the distance formula,
D%5E2=%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2
Distance from (x,y) to (3,2),
Z%5E2=%28x-3%29%5E2%2B%28y-2%29%5E2
Distance from (x,y) to (0,y),
W%5E2=%28x-0%29%5E2%2B%28y-y%29%5E2
W%5E2=x%5E2
.
.
Z=W
Z%5E2=W%5E2
%28x-3%29%5E2%2B%28y-2%29%5E2=x%5E2
x%5E2-6x%2B9%2By%5E2-4y%2B4=x%5E2
highlight%28y%5E2-4y-6x%2B13=0%29