# SOLUTION: how can i solve this? I'm confused! the sum of the degree measures of the three angles of a triangle is 180. Find the degree of the measures of the third angle given the degree

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 Question 363961: how can i solve this? I'm confused! the sum of the degree measures of the three angles of a triangle is 180. Find the degree of the measures of the third angle given the degree measure of the two angles. a. 7x^2 + 6x + 45; 5x^2 + 10x - 55 b. 3x^3 - 15x^2 - 24x + 5; 9x^2 + 30x + 36 c. 9x^4 + 58x^3 + 24x^2 - 45x + 15; 11x^4 - 47x^3 + 16x^2 - 94x + 27Answer by Alan3354(31518)   (Show Source): You can put this solution on YOUR website!the sum of the degree measures of the three angles of a triangle is 180. Find the degree of the measures of the third angle given the degree measure of the two angles. a. 7x^2 + 6x + 45; 5x^2 + 10x - 55 1 angle is 7x^2 + 6x + 45 degrees. The 2nd angle is 5x^2 + 10x - 55 Add those = 12x^2 + 16x - 10 degrees The 3rd angle is 180 - the sum Angle 3 = 180 - (12x^2 + 16x - 10) degrees = 190 - 12x^2 - 16x degrees ------------------------------- Do the others the same way. b. 3x^3 - 15x^2 - 24x + 5; 9x^2 + 30x + 36 c. 9x^4 + 58x^3 + 24x^2 - 45x + 15; 11x^4 - 47x^3 + 16x^2 - 94x + 27