SOLUTION: A baseball diamond is in the shape of a square, 90 feet on a side.
what is the direct distance from the home plate to second base?
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-> SOLUTION: A baseball diamond is in the shape of a square, 90 feet on a side.
what is the direct distance from the home plate to second base?
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Question 363888: A baseball diamond is in the shape of a square, 90 feet on a side.
what is the direct distance from the home plate to second base? Found 2 solutions by stanbon, ewatrrr:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A baseball diamond is in the shape of a square, 90 feet on a side.
what is the direct distance from the home plate to second base?
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That distance is the hypotenuse of a 90 by 90 right triangle.
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h = sqrt[90^2 + 90^2]
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h = sqrt[2*90^2]
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h = 90*sqrt(2)
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h = 127.28 ft.
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Cheers,
Stan H.
Hi,
Let c represent the direct distance from the home plate to second base
applying the Pythagorean Theorem, c being the hypotenuse.
90^2 + 90^2 = c^2
127.279 ft = c, the direct distance from the home plate to second base