SOLUTION: Find the area of the triangle with vertices of A(0, 0), B(3, 4), and C(4, 3).

Question 363088: Find the area of the triangle with vertices of A(0, 0), B(3, 4), and C(4, 3).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
3.5 sq units
--------------
Arrange the points like this:
0 3 4 0
0 4 3 0
(The 1st point is repeated)
-------
Add the diagonal products from lower left to upper right:
0 + 16 + 0 = 16
Add the diagonal products from upper left to lower right:
0 + 9 + 0 = 9
---------
Get the absolute value of the difference:
|9 - 16| = 7
Area = 7/2 = 3.5 sq units
------------------
This works for any # of points, any shape.

RELATED QUESTIONS
Given triangle ABC with vertices A(−3, 0), B(0, 6), and C(4, 6). Find the equations of (answered by Alan3354,ikleyn)

Given triangle ABC with vertices A(−3, 0), B(0, 6), and C(4, 6). a. Find the... (answered by Alan3354)

Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3,... (answered by Cromlix,MathTherapy)

Find the area of a parallelogram with vertices (0, 0), (3, 3), (4, 6), and (7, 9) (answered by CubeyThePenguin,ikleyn)

Find the area of the triangle with vertices (0, 0), (5, 3) and (2,... (answered by Fombitz)

Find the area of the pentagon ABCDE with vertices A = (1, 2), B = (0, 0), C = (1, 4), D... (answered by Alan3354)

Find the area of the triangle whose vertices are (3; 4) ; (-2; 5) ;... (answered by Fombitz)

Find the area of a triangle whose vertices have coordinates (0,9), (0,-4), and... (answered by Edwin McCravy)