SOLUTION: what is the height of a triangle, where the area is 56 inches squared and a base of 14 inches?

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Question 359293: what is the height of a triangle, where the area is 56 inches squared and a base of 14 inches?
Answer by geforcewong(2)   (Show Source): You can put this solution on YOUR website!
The Area of a triangle is one-half the base times the height of the triangle.
So A=(1/2)bh, where A= Area, b = base, h = height.
Since you are given the Area (A =56 inches^2)
and you are given the base (b = 14 inches),


You can find the height (h) by plugging the given Area and base into the equation:


A = (1/2)bh
So,


Plug in A= 56 inches^2 and b = 14 inches:
56 inches^2 = (1/2)(14 inches)h


Simplified:
56 inches^2 = (7 inches)h


Dividing both sides by 7 inches:
56 inches^2 / 7 inches = h


Simplifying units of measurement (inches^2 divided by inches = inches):
h = (56/7) inches


Simplified:
h = 8 inches


Check your work: A = (1/2)(14)(8) = (7)(8) = 56 = Area that was given.


Therefore, when the area of a triangle is 56 inches squared and has a base of 14 inches, the height will be 8 inches.

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