# SOLUTION: Each leg of an isosceles triangle exceeds twice the base by 5 inches. Find each side of the triangle if the perimeter is 5 feet.

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 Click here to see ALL problems on Triangles Question 345042: Each leg of an isosceles triangle exceeds twice the base by 5 inches. Find each side of the triangle if the perimeter is 5 feet.Answer by ankor@dixie-net.com(15652)   (Show Source): You can put this solution on YOUR website!Each leg of an isosceles triangle exceeds twice the base by 5 inches. Find each side of the triangle if the perimeter is 5 feet. : Change 5 ft to 60 inches : Let b = length of the base then (2b+5) = the other two sides : The perimeter: 2(2b+5) = b = 60 4b + 10 + b = 60 4b + b = 60 - 10 5b = 50 b = b = 10 inches is the base and 2(10) + 5 = 25 inches are the other two sides ; Check, find the perimeter: 25 + 25 + 10 = 60 inches