SOLUTION: how would you find the area of the triangle when the base of the triangle is x+6 and both of the sides are x+8. The height is 2x. you dont know what x is.

Question 298075: how would you find the area of the triangle when the base of the triangle is x+6 and both of the sides are x+8. The height is 2x. you dont know what x is.
Found 2 solutions by scott8148, doncjones:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
by Pythagoras ___ [(x+6) / 2]^2 + (2x)^2 = (x+8)^2

[(x^2 + 12x + 36) / 4] + 4x^2 = x^2 + 16x + 64

x^2 + 12x + 36 + 16x^2 = 4x^2 + 64x + 256

13x^2 - 52x - 220 = 0

use quadratic formula to find x
Answer by doncjones(3) (Show Source): You can put this solution on YOUR website!
Seems like the area of a triangle is 1/2 base x height. The base is (x+6) and the height is 2x. So, (1/2)(x+6)(2x) = (x)(x+6) = x^2 + 6x.
That should be it.
Don
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