SOLUTION: The perimeter of a triangle is 75 units. The sides have lengths a, b, and c. The ratio of b to a is 3:5, and the ratio of c to a is 7:5. Find the length of each side.
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-> SOLUTION: The perimeter of a triangle is 75 units. The sides have lengths a, b, and c. The ratio of b to a is 3:5, and the ratio of c to a is 7:5. Find the length of each side.
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Question 254628: The perimeter of a triangle is 75 units. The sides have lengths a, b, and c. The ratio of b to a is 3:5, and the ratio of c to a is 7:5. Find the length of each side. Found 2 solutions by drk, JimboP1977:Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! The perimeter is 75 can be expressed as =
Now
b/a = 3/5 means that
(i) b = (3/5)a
and
c/a = 7/5 means that
(ii) c = (7/5)a
by substituting (i) and (ii) into perimeter we get
and then
multiply by 5 to get
You can put this solution on YOUR website! a:b:c = 5:3:7
5z+3z+7z=75 where z is the common multiple.
15z=75
z=5
So a = 5*5 = 25
b = 3*5 = 15
c = 7*5 = 35
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