SOLUTION: what is the heigth of an equalateral triangle that is 30 ft wide by 30 ft on each side and formula to solve this problem?
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Question 240911: what is the heigth of an equalateral triangle that is 30 ft wide by 30 ft on each side and formula to solve this problem?
Found 2 solutions by edjones, solver91311:
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
The height bisects the base of an equilateral triangle.
b=15 c=30
a^2+b^2=c^2
a^2+225=900
a^2=675
a=sqrt(3^3*5^2) prime factors of 675.
=15sqrt(3)'
.
Ed
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The altitude of an equilateral triangle is also a perpendicular bisector of the base. Therefore, the height is the measure of one leg of a right triangle where the hypotenuse is the measure of one side of the equilateral triangle and the other leg measures one-half of the side of the equilateral triangle.
So, applying Pythagoras, given the measure of the side, 
, the height, 
is:
^2}\ =\ \sqrt{\frac{3s^2}{4}}\ =\ \frac{s\sqrt{3}}{2})
Hence, for a 30 foot equilateral triangle, the height is:
John
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