SOLUTION: The solution of: 3(x-3)≥15 is [?,∞) I am thoroughly stuck on this problem! Any assistance on how to go about solving this problem so that I have a better und

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3(x-3)≥15 is [?,∞)
.
Solving for x:
3(x-3)≥15
x-3 ≥ 5
x ≥ 8
.
Therefore, x is "greater than or equal" to eight.
Or, you can write it in range notation:
x = [8,∞)
Where
[ symbol means "include" the number
and
) symbol means "do not include" the number