SOLUTION: 1.) a triangle legs 8 base of 10 vertex angle at 78 degrees what is the base angle X in degrees. 2. A triangle with one of the leg is 8 base is 10 the vertex angle 63 degrees ba

Question 204845: 1.) a triangle legs 8 base of 10 vertex angle at 78 degrees what is the base angle X in degrees.
2. A triangle with one of the leg is 8 base is 10 the vertex angle 63 degrees base angle is 54 degrees What is the other leg X?
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Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
(1) sum of angles in triangle is 180 degrees
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78 +x +x =180,,x= 51 degrees, ( 2 legs @ 8 cause isosceles triangle with base angles the same)
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check (sin 78 / 10) = .0978,,,(sin 51 / 8 = .0971),,,,ok (obeys law of sines)
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(2) Please check to see that problem is correct
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sum of angles,,(63 + 54 +x ) =180,,,cause x to be 63.
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With the base opposite vertex, it conflicts with law of sines, to have base smaller than sides.
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if base angles are 63,and sides are 10,,,sin 63 /10 = .0891..
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the side opposite the 54 degree angle is ,,sin 54/x = .0891,,,or x=9.08
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Again,, please review the problem
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