SOLUTION: There is a right triangle. The short leg is 7 and the long leg is 10. X is across from the right angle. How do I find X?

SOLUTION: There is a right triangle. The short leg is 7 and the long leg is 10. X is across from the right angle. How do I find X?

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Question 197934: There is a right triangle. The short leg is 7 and the long leg is 10. X is across from the right angle. How do I find X?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
The sides of a right triangle are defined by the following formula:
a^2+b^2=C^2 where a & b are the 2 short legs & c is the hypotenuse ( the side opposite the right angle)
7^2+10^2=c^2
49=100=c^2
149=c^2
sqrt149=c
12.2=c ans.
Proof:
49+100=12.2^2
149~149
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