SOLUTION: Hi, if theta is an acute angle and sin theta =1/2, then cos theta= I have drawn a right triangle with the hypotenus on the right. It has a one on the bottom and a two on the hyp

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Question 165593: Hi, if theta is an acute angle and sin theta =1/2, then cos theta=
I have drawn a right triangle with the hypotenus on the right. It has a one on the bottom and a two on the hypotenuse. Then I tried 1^2+b^2=2^2 and ended up with square root of b^2 =square root of 3. I do not know where to go from there

Thankyou.
Answer by Earlsdon(6103) (Show Source):
You can put this solution on YOUR website!
You have done ok so far!
In your triangle, you have , , and .
To see how we get b, you have:
Take the square root of both sides.

The sin of theta (I'll call it A because I can't do a theta symbol) is given as because the sine of the angle is the side opposite the angle (a = 1) over the hypotenuse (c = 2), so you get
The cosine of this angle (A) is the side adjacent to the angle ( over the hypotenuse (c = 2), so...