SOLUTION: given the figure Triangle ABC, with point D on line segment AB and point E on line segment AC, DE parallel to BC, AD=4, DB=5, and EC=7, then AC=?
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Question 148395: given the figure Triangle ABC, with point D on line segment AB and point E on line segment AC, DE parallel to BC, AD=4, DB=5, and EC=7, then AC=? Answer by aswathytony(47) (Show Source):
By proprotional intercept property, DB / AB = EC / AC
AB = AD + DB = 4 + 5 = 9
SUBSTITUTING THE GIVEN VALUES
5 /9 = 7 / AC
AC = (9 * 7 ) / 5
= 63 / 5 = 12.6
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