SOLUTION: given the figure Triangle ABC, with point D on line segment AB and point E on line segment AC, DE parallel to BC, AD=4, DB=5, and EC=7, then AC=?

Question 148395: given the figure Triangle ABC, with point D on line segment AB and point E on line segment AC, DE parallel to BC, AD=4, DB=5, and EC=7, then AC=?
Answer by aswathytony(47) (Show Source): You can put this solution on YOUR website!

By proprotional intercept property, DB / AB = EC / AC
AB = AD + DB = 4 + 5 = 9
SUBSTITUTING THE GIVEN VALUES
5 /9 = 7 / AC
AC = (9 * 7 ) / 5
= 63 / 5 = 12.6

RELATED QUESTIONS
ABC is a triangle with base = BC . A line segment DE is drawn parallel to Side AC. D is... (answered by ikleyn)

In triangle ABC, D is a point on segment AC and E is a point on CB such that DE and AB... (answered by KMST,solver91311,ikleyn)

A triangular lot ABC with BC=400m and B=50° is divided into two parts by the line... (answered by CPhill)

In ΔABC shown below, point A is at (0, 0), point B is at (x2, 0), point C is at (x1,... (answered by greenestamps)

In triangle ABC,D and E are points on the sides AB and AC respectively such that DE... (answered by MathLover1)

Gina wrote the following paragraph to prove that the segment joining the midpoints of two (answered by mykasha)

In a triangle ABC, D is a point on side AB and E is the point on AC. DE parallel to BC.... (answered by greenestamps)

Look at the figure shown below. The figure shows triangle ABC. A segment joins point... (answered by richard1234)

Gina wrote the following paragraph to prove that the segment joining the midpoints of two (answered by ikleyn)