SOLUTION: I have 2 triangles in a trapezoid. there is an "X" in the trapezoid coneecting corners and I need to find the height of 2 verticle triangles ( >< ) and one has the base of nine and

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Question 142911: I have 2 triangles in a trapezoid. there is an "X" in the trapezoid coneecting corners and I need to find the height of 2 verticle triangles ( >< ) and one has the base of nine and the other a base of 15 (the bases of the triangles are the parallel lines in the trapezoid which has an area of 27) I need to find the height of a triangle with the base of 15!
Answer by psbhowmick(878)   (Show Source): You can put this solution on YOUR website!

Let the trapezoid be ABCD.
Given: AB = 15 units, CD = 9 units, Area of trapezoid ABCD = 27 sq units.
Draw CE, perpendicular to AB from C at E. Let CE = h units.
Observe that CE is the height for both the triangles ABC and ACD as their bases are parallel.

Area of trapezoid ABCD
= Area of triangle ABC + Area of triangle ACD
= sq units [since ]
= sq units
= sq units
= sq units

But area of trapezoid ABCD is given to be 27 sq units.
So,
units

Thus, required height is 2.25 units.

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