SOLUTION: The hypotenuse of a right triangle is 12cm. One side is 2cm longer than the other. FInd the lengths of the two other sides, to the nearest hundreth. I keep getting the wrong anw

Question 123179: The hypotenuse of a right triangle is 12cm. One side is 2cm longer than the other. FInd the lengths of the two other sides, to the nearest hundreth.
I keep getting the wrong anwser.
Found 2 solutions by johnnico6426, Fombitz:
Answer by johnnico6426(16) (Show Source): You can put this solution on YOUR website!
Hypotenuse: z
leg: x and y
First of all, since the hypotenuse of the right triangle is 12 cm, then the other two sides should be less than. Second, since one of the side of the triangle is 2 cm longer than the other leg, then one can conclude that the length of the two sides are as follow: y = a + 2 and x = a. Plug the value of x, y, and z in . Simplify.
When you plug them in and simplify, you should get 2a^2 + 4a - 140 = 0. The next step is either plug it in the quadratic formula or factor. Regardless of what method you get, you should end up with a=SQRT(71)-1 and -SQRT(71)+1). Since it is a side of a triangle, disregard the negative sign in front of SQRT(71) + 1.
Solution:
a=SQRT(71)-1
a=SQRT(71)+1
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Call the one side, x.
THe other side is then x+2.
From the Pythagorean theorem, you know that

Expand the perfect square.
Simplify.
Bright all terms to one side.
Divide by 2.
Use the quadratic equation.

Since a negative length does not make sense in this application, use only the positive results.
x=7.43
x+2=9.43
Check the results to verify your answer.

Look likes that close enough.
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