SOLUTION: I keep coming up with a solution that is different from the answer key. Here is the problem: Find the area of an isosceles triangle where the base is 3 and the sides are the square

Question 122278: I keep coming up with a solution that is different from the answer key. Here is the problem: Find the area of an isosceles triangle where the base is 3 and the sides are the square root of 11.
Thanks
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Triangle is ABC.
AB side is .
AC side is .
BC side is .
Split BC in half at point Z to form two equal line segments BZ=ZC=3/2.
You can now form two right triangles, ABZ and AZC.
Call the length of AZ side, H.
Using the Pythagorean theorem, you can find the height, H, because,

For the area of the original isoceles triangle,

A is 2.25 square units.
Does that answer match the answer key?
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