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The coordinates of points A, B, and C are A(-4, 6), B(-1, 2), and C(2,-2).
(a) Show that AB = BC by using the distance formula.
(b) Show that AB + BC = AC by using the distance formula.
(c) What can you conclude from parts (a) and (b)?
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The problem can be easily solved without the distance formula,
which is, actually, non-necessary and excessive calculation job.
Vector AB with starting point A and ending point B is
<(-1-(-4),2-6> = <3,-4>.
Vector BC with starting point B and ending point C is
<(2-(-1),-2-2> = <3,-4>.
Thus vectors AB and BC are congruent: they represent the same vector.
It implies that
(a) Their lengths are the same, AB = BC (without using the distance formula).
(b) AB + BC = AC (without using the distance formula).
(c) The conclusion is that three points A, B and C lie on the same straight line and point C is the midpoint of segment AC.
Solved, by a simple way.