SOLUTION: A triangle ABC has its right angle at C and the vertices A(3, 8) and B(9, 5) . If no sides of the triangle are parallel to the axes, what is the product of the slopes of all three

Question 1202901: A triangle ABC has its right angle at C and the vertices A(3, 8) and B(9, 5) . If no sides of the triangle are parallel to the axes, what is the product of the slopes of all three sides of triangle ABC ?
(A) -2
(B) -1/2
(C) -1/8
(D) 1/2
(E) 2
Found 2 solutions by ikleyn, math_helper:
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
A triangle ABC has its right angle at C and the vertices A(3, 8) and B(9, 5).
If no sides of the triangle are parallel to the axes, what is the product
of the slopes of all three sides of triangle ABC ?
(A) -2
(B) -1/2
(C) -1/8
(D) 1/2
(E) 2
~~~~~~~~~~~~~~~~~~~

The slopes m(AC) and m(BC) gives the product of -1, since the angle C is the right angle. Therefore, m(AB)*m(AC)*m(BC) = -m(AB) = = = . ANSWER. . option (D).

Solved

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Tutor's @math_helper notice is right, so I made the necessary corrections.

Now you see a correct repaired version.

Thanks to tutor @math_helper.

Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!

The line "Therefore, m(AB)*m(AC*m(BC) = -m(BC)"
should read m(AB)*m(AC)*m(BC) = m(AB)*(-1) = ...
The final answer is correct but there was a typo in the intermediate step.
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