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if an angle θ is a principal angle that lies in the quadrant 3 such that 0 degrees ≤ θ ≤ 360 degrees,
determine the exact value of x, y and r for tan θ= 2/3 and draw the diagram
I got for x=3 y=2 and r= square root of 13 not sure how to draw it though
Thanks
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= = .
So, if the angle is in Quadrant I, then you can take x = 3, y = 2.
But since the angle is in Quadrant III ( ! given !), you must take x= -3 and y= -2.
So, your point is, actually, (x,y) = (-3,-2).
Thus, from the origin, you should move 3 units left to get x= -3, and then move 2 units down to get y= -2.
This point will be that you should mark on coordinate plane.
Do as instructed, and you will get your sough point.
Solved, explained and completed.