SOLUTION: Given that since (x+y)=0.7 cm, and angle ACD is obtuse, what is the area of triangle ACD: the question link: https://cdn.discordapp.com/attachments/849084987319779368/9093730527631
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Question 1187733: Given that since (x+y)=0.7 cm, and angle ACD is obtuse, what is the area of triangle ACD: the question link: https://cdn.discordapp.com/attachments/849084987319779368/909373052763136030/Screenshot_2021-11-14_at_5.23.14_PM.png
pls refer to the question link for the diagram for the question,if you have the answer pls email me at : leong.marianne@gmail.com
Thank you.
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Sunday, April 2, 2017
7:06 PM
So 
and \ =\ \sin(x\,+\,y)\ =\ 0.7)
, but choose "+" for acute angles and "-" for obtuse angles.
Hence, \ =\ -\sqrt{0.51})
and \ \approx\ 120.7^\circ)
Use the Law of Cosines to find the measure of side AD
})
where 
is the included angle.
(2)(-\sqrt{.51}))
You can do your own arithmetic.
Use Heron's Formula to find the area now that you have the three sides.
(s\,-\,b)(s\,-\,c))
Where 
is the semi-perimeter, 
Again, you can do your own arithmetic
John
My calculator said it, I believe it, that settles it
From
I > Ø
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