Hi A(2,9) B(9,7) MidP(5.5, 8) m(AB) = (2/-7) perpendicular bisector: y-8 = (7/2)(x-11/2) 0r y = (7/2)x -45/4 B(9,7) and C(2,0) MidP(5.5, 3.5) m(AB) = (7/7) = 1 perpendicular bisector: y-(7/2) = -(x-11/2) 0r y = -x + 9 -x + 9 = (7/2)x - 45/4 x = 9/2 and y = 9/2 point of intersection of the two perpendicular bisectors is P(9/2,9/2) Wish You the Best in your Studies.