SOLUTION: complete the following statements
6a^2+13a+6=(2a+3)( )
4m^2+5mn-6n^2=(m+2n)( )
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Question 117627: complete the following statements
6a^2+13a+6=(2a+3)( )
4m^2+5mn-6n^2=(m+2n)( )
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
#1
Looking at we can see that the first term is and the last term is where the coefficients are 6 and 6 respectively.
Now multiply the first coefficient 6 and the last coefficient 6 to get 36. Now what two numbers multiply to 36 and add to the middle coefficient 13? Let's list all of the factors of 36:
Factors of 36:
1,2,3,4,6,9,12,18
-1,-2,-3,-4,-6,-9,-12,-18 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 36
1*36
2*18
3*12
4*9
6*6
(-1)*(-36)
(-2)*(-18)
(-3)*(-12)
(-4)*(-9)
(-6)*(-6)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 13? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 13
First Number | Second Number | Sum | 1 | 36 | 1+36=37 |
2 | 18 | 2+18=20 |
3 | 12 | 3+12=15 |
4 | 9 | 4+9=13 |
6 | 6 | 6+6=12 |
-1 | -36 | -1+(-36)=-37 |
-2 | -18 | -2+(-18)=-20 |
-3 | -12 | -3+(-12)=-15 |
-4 | -9 | -4+(-9)=-13 |
-6 | -6 | -6+(-6)=-12 |
From this list we can see that 4 and 9 add up to 13 and multiply to 36
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
-------------------------------
Answer:
So factors to which means the missing factor is
#2
Looking at we can see that the first term is and the last term is where the coefficients are 4 and -6 respectively.
Now multiply the first coefficient 4 and the last coefficient -6 to get -24. Now what two numbers multiply to -24 and add to the middle coefficient 5? Let's list all of the factors of -24:
Factors of -24:
1,2,3,4,6,8,12,24
-1,-2,-3,-4,-6,-8,-12,-24 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -24
(1)*(-24)
(2)*(-12)
(3)*(-8)
(4)*(-6)
(-1)*(24)
(-2)*(12)
(-3)*(8)
(-4)*(6)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to 5? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 5
First Number | Second Number | Sum | 1 | -24 | 1+(-24)=-23 |
2 | -12 | 2+(-12)=-10 |
3 | -8 | 3+(-8)=-5 |
4 | -6 | 4+(-6)=-2 |
-1 | 24 | -1+24=23 |
-2 | 12 | -2+12=10 |
-3 | 8 | -3+8=5 |
-4 | 6 | -4+6=2 |
From this list we can see that -3 and 8 add up to 5 and multiply to -24
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
-------------------------------
Answer:
So factors to which means the missing factor is
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